Example has 1,a,b,c. Will allow if there is an a, or b, or c, or a and b, or a and c, or b and c, or all three. Introduction to Combinatorics and Probability Theory. This article is a step-by-step guide explaining how to compute the probability that, for example, exactly 4 out of 6 picks win, or how to calculate the likelihood that at least 4 of 6 bets win. To help your understanding of this topic you will need to comprehend the basics of football result probability calculations, which I explained in.
Calculator Use
Like the Combinations Calculator the Permutations Calculator finds the number of subsets that can be taken from a larger set. However, the order of the subset matters. The Permutations Calculator finds the number of subsets that can be created including subsets of the same items in different orders.
- Factorial
- There are n! ways of arranging n distinct objects into an ordered sequence, permutations where n = r.
- Combination
- The number of ways to choose a sample of r elements from a set of n distinct objects where order does not matter and replacements are not allowed.
- Permutation
- The number of ways to choose a sample of r elements from a set of n distinct objects where order does matter and replacements are not allowed. When n = r this reduces to n!, a simple factorial of n.
- Combination Replacement
- The number of ways to choose a sample of r elements from a set of n distinct objects where order does not matter and replacements are allowed.
- Permutation Replacement
- The number of ways to choose a sample of r elements from a set of n distinct objects where order does matter and replacements are allowed.
- n
- the set or population
- r
- subset of n or sample set
Permutations Formula:
For n ≥ r ≥ 0.
Calculate the permutations for P(n,r) = n! / (n - r)!. 'The number of ways of obtaining an ordered subset of r elements from a set of n elements.'[1]
Permutation Problem 1
Choose 3 horses from group of 4 horses
In a race of 15 horses you beleive that you know the best 4 horses and that 3 of them will finish in the top spots: win, place and show (1st, 2nd and 3rd). So out of that set of 4 horses you want to pick the subset of 3 winners and the order in which they finish. How many different permutations are there for the top 3 from the 4 best horses?
For this problem we are looking for an ordered subset of 3 horses (r) from the set of 4 best horses (n). We are ignoring the other 11 horses in this race of 15 because they do not apply to our problem. We must calculate P(4,3) in order to find the total number of possible outcomes for the top 3 winners.
P(4,3) = 4! / (4 - 3)! = 24 Possible Race Results
If our 4 top horses have the numbers 1, 2, 3 and 4 our 24 potential permutations for the winning 3 are {1,2,3}, {1,3,2}, {1,2,4}, {1,4,2}, {1,3,4}, {1,4,3}, {2,1,3}, {2,3,1}, {2,1,4}, {2,4,1}, {2,3,4}, {2,4,3}, {3,1,2}, {3,2,1}, {3,1,4}, {3,4,1}, {3,2,4}, {3,4,2}, {4,1,2}, {4,2,1}, {4,1,3}, {4,3,1}, {4,2,3}, {4,3,2}
Permutation Problem 2
Choose 3 contestants from group of 12 contestants
At a high school track meet the 400 meter race has 12 contestants. The top 3 will receive points for their team. How many different permutations are there for the top 3 from the 12 contestants?
For this problem we are looking for an ordered subset 3 contestants (r) from the 12 contestants (n). We must calculate P(12,3) in order to find the total number of possible outcomes for the top 3.
P(12,3) = 12! / (12-3)! = 1,320 Possible Outcomes
Permutation Problem 3
Choose 5 players from a set of 10 players
An NFL team has the 6th pick in the draft, meaning there are 5 other teams drafting before them. If the team believes that there are only 10 players that have a chance of being chosen in the top 5, how many different orders could the top 5 be chosen?
For this problem we are finding an ordered subset of 5 players (r) from the set of 10 players (n).
Combination And Permutation Calculator Soup
P(10,5)=10!/(10-5)!= 30,240 Possible Orders
Football Permutations Calculator Online
References
[1] For more information on permutations and combinations please see Wolfram MathWorld: Permutation.
Find below some useful betting charts and tables showing the number of selections for various permutations. Also shown are the numbers of bets for some of the well know bet types offered and promoted by bookmakers like Lucky 15, 31, 63, yankee, canadian, heinz, goliath. TIP:Have you noticed that bookmakers advertise and promote multi selection bets and permutations everywhere and when you see a big win announced in the newspaper its always about a lucky gambler who placed a small bet on a multi-selection permutation like a Super-Heinz and who won £500,000 on a £60 bet??? There is a good reason for this. Multi selection bets and permutations usually offer the gambler very poor value and making profit from such bets is very difficult. Just 1 selection failing to win can effectively wipe out any profits on certain permutations. The bookmakers don't mind the occasional big winner as they make a fortune from the millions of other gamblers who are wasting their money on such permutations. Our advice: Don't bother placing these type of bets and stick to Singles, Each/Way, forecasts with maybe the odd double or treble. If you do wish to place bets using some of the large permutation bet types like Heinz etc, always stick to very small stakes and its probably best to consider them as fun bets. Systems like Racing Synergy below use sound logic to select value horses to bet as singles either to win or EW. Take a look today. |